👆👆👆所有的数学公式、特殊符号均可在上面找到。
$内容$$a+b^2$ = a + b 2 a + b^2 a + b 2
$$\begin {array}{c}
\nabla \times \vec {\mathbf {B}} -\, \frac 1c\, \frac {\partial \vec {\mathbf {E}}}{\partial t} & = \frac {4\pi }{c}\vec {\mathbf {j}} \nabla \cdot \vec {\mathbf {E}} & = 4 \pi \rho \\ \nabla \times \vec {\mathbf {E}}\, +\, \frac 1c\, \frac {\partial \vec {\mathbf {B}}}{\partial t} & = \vec {\mathbf {0}} \\ \nabla \cdot \vec {\mathbf {B}} & = 0
\end {array}$$ ∇ × B ⃗ − 1 c ∂ E ⃗ ∂ t = 4 π c j ⃗ ∇ ⋅ E ⃗ = 4 π ρ ∇ × E ⃗ + 1 c ∂ B ⃗ ∂ t = 0 ⃗ ∇ ⋅ B ⃗ = 0 \begin {array}{c} \nabla \times \vec {\mathbf {B}} -\, \frac1c\, \frac {\partial\vec {\mathbf {E}}}{\partial t} & = \frac {4\pi}{c}\vec {\mathbf {j}} \nabla \cdot \vec {\mathbf {E}} & = 4 \pi \rho \\ \nabla \times \vec {\mathbf {E}}\, +\, \frac1c\, \frac {\partial\vec {\mathbf {B}}}{\partial t} & = \vec {\mathbf {0}} \\ \nabla \cdot \vec {\mathbf {B}} & = 0 \end {array} ∇ × B − c 1 ∂ t ∂ E ∇ × E + c 1 ∂ t ∂ B ∇ ⋅ B = c 4 π j ∇ ⋅ E = 0 = 0 = 4 π ρ
^上标，后面如果很长，要用把内容放到{}里。
_下标，后面如果很长，要用把内容放到{}里。
$a^2+b^{20}$
$a+b^{x+y+z^2}$
$H_{2}O$
$a_1,a_2,a_3$
$a_{2n+1}$ a 2 + b 20 a^2+b^{20} a 2 + b 2 0
a + b x + y + z 2 a+b^{x+y+z^2} a + b x + y + z 2
H 2 O H_{2}O H 2 O
a 1 , a 2 , a 3 a_1,a_2,a_3 a 1 , a 2 , a 3
一阶导数
$f'$
二阶导数
$f''$
矢量表示
$\vec {F}$
$\vec {a}+\vec {b}=\vec {c}$
一阶导数f ′ f' f ′ f ′ ′ f'' f ′ ′
矢量表示F ⃗ \vec{F} F
a ⃗ + b ⃗ = c ⃗ \vec{a} + \vec{b} = \vec{c} a + b = c
矩阵有很多种表示，详细见官网 。
这里用的是MIT公开课中的书写方法。
$$\begin {bmatrix}
a & b \\ <==这里的「\\ 」为换行的意思
c & d
\end {bmatrix}$$
$$\begin {bmatrix}
a & b & f \\
c & d & g
\end {bmatrix}$$
行列式如下
$$\begin {vmatrix}
a & b \\
c & d
\end {vmatrix}$$
$$\begin {vmatrix}
a & b \\
c & d
\end {vmatrix}=a*d-b*c$$ [ a b c d ] \begin{bmatrix} a & b \\ c & d \end{bmatrix} [ a c b d ]
[ a b f c d g ] \begin{bmatrix} a & b & f \\ c & d & g \end{bmatrix} [ a c b d f g ]
∣ a b c d ∣ \begin{vmatrix} a & b \\ c & d \end{vmatrix} ∣ ∣ ∣ ∣ ∣ a c b d ∣ ∣ ∣ ∣ ∣
∣ a b c d ∣ = a ∗ d − b ∗ c \begin{vmatrix} a & b \\ c & d \end{vmatrix}=a*d-b*c ∣ ∣ ∣ ∣ ∣ a c b d ∣ ∣ ∣ ∣ ∣ = a ∗ d − b ∗ c
$$
\sin {a} \\
\cos {a} \\
\tan {a} \\
\arcsin {a}\\
\arccos {a}\\
\arctan {a}
$$
sin a cos a tan a arcsin a arccos a arctan a \sin{a} \\ \cos{a} \\ \tan{a} \\ \arcsin{a}\\ \arccos{a}\\ \arctan{a} sin a cos a tan a arcsin a arccos a arctan a
$$
\alpha \\
\delta \\
\gamma \\
\theta \\
\pi \\
\Pi \\
\rho \\
\upsilon \\
\omega
$$ α δ γ θ π Π ρ υ ω \alpha \\ \delta \\ \gamma \\ \theta \\ \pi \\ \Pi\\ \rho \\ \upsilon \\ \omega α δ γ θ π Π ρ υ ω
$\sin ^2{\theta } + \cos ^2{\theta } = 1$ sin 2 θ + cos 2 θ = 1 \sin^2{\theta} + \cos^2{\theta} = 1 sin 2 θ + cos 2 θ = 1
$$
\ln {2} \\
e^{2} \\
\log _{2}4
\sqrt {3}\\
\sqrt [5]{x}
$$ ln 2 e 2 log 2 4 3 x 5 \ln{2} \\ e^{2} \\ \log_{2}4\\ \sqrt{3}\\ \sqrt[5]{x} ln 2 e 2 log 2 4 3 5 x
$$
\frac {1}{e}\\
\frac {\sin {a}}{\cos {a}} = \tan {a}\\
\frac {1}{x^2+y^2}
$$
1 e sin a cos a = tan a 1 x 2 + y 2 \frac{1}{e}\\ \frac{\sin{a}}{\cos{a}} = \tan{a}\\ \frac{1}{x^2+y^2} e 1 cos a sin a = tan a x 2 + y 2 1
$$
\int {x}dx = x^2 +C\\
\iint {xy}dxdy\\
\iiint {xyz}dxdydz
$$ ∫ x d x = x 2 + C ∬ x y d x d y ∭ x y z d x d y d z \int{x} dx = x^2 +C\\ \iint{xy} dxdy\\ \iiint{xyz} dxdydz ∫ x d x = x 2 + C ∬ x y d x d y ∭ x y z d x d y d z
$$
F(n)=\begin {dcases}
1 & \text {if}\quad n=0,1 \\
n*F(n-1) & \text {if} \quad n>=1
\end {dcases}\\ \\
F(n) = \Pi _{\substack {i=1}}^{n}n
$$ F ( n ) = { 1 if n = 0 , 1 n ∗ F ( n − 1 ) if n > = 1 F ( n ) = Π i = 1 n n F(n)=\begin{dcases} 1 & \text{if}\quad n=0,1 \\ n*F(n-1) & \text{if} \quad n>=1 \end{dcases}\\\\ F(n) = \Pi_{\substack{i=1}}^{n}n F ( n ) = { 1 n ∗ F ( n − 1 ) if n = 0 , 1 if n > = 1 F ( n ) = Π i = 1 n n